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& Ù µ & å Î Q m C Q / & ì A & ½ À N 3 J ô m!. Arbitragefree pricing for physical assets 13 • Two new elements enter the pricing relation – Storage costs (c) like insurance. Share your videos with friends, family, and the world.

/pn{ m} 0} yp{h hzpy yh m} c hxp{n {h }m oh f Þ Yo u m a y o p t o u t a n y t i m e B y s i g n i n g u p f o r t h i s n e w s l e t t e r, y o u a g r e e t o t h e Te r m s a n d C o n d i t i o n s a n d P r i v a c y P o l i c y zpy ff h / czp ADVERTISEMENT. A r ec o m m o n l yu s e di nB L U st or e d i s t r i b u t em o r el i g h t towards the normal direction with preferred polarization As an example, F can be reduced to 096 sr by applying two. 3 W E SEEK TO G R O W IN LO VE 1 ó ¡­ C¡Í Ô f ó 1 ã ¾© !.

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You collect Se (rd)T (when you borrow a stock you must pay its dividends to the lender!) and pay F(T) to close the position • So in equilibrium we must have Se (rd)T= F(T) for all T – Concept check if r>d what must we have contango or backwardation?. J k k k k l ­ mo ý ^@ 4*bm_. Ù 4 7 1 ¨ · ° æ t Ø Þ · Û ) Ð ¯ f u 0 m b Û ¬ ¯ f u 1 Ù 4 · S Ê 7 è â ó 3 ¸ t 1 v ³ ² ´ ³ ¸ Ï £ Þ ¯ f u Ç ¨ t Ù 4 · ¸ ´ ­ ¯ Ë ´ ³ ¸ Ï £ Í Ê ¯ f u ¨ 7 s < · Õ â w t r w t R ¨ & ó ¸ n Í ´ ¯ f u ¢ Ù Ë s < ¸.

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2 (a) Define uniform continuity on R for a function f R → R (b) Suppose that f,g R → R are uniformly continuous on R (i) Prove that f g is uniformly continuous on R (ii) Give an example to show that fg need not be uniformly continuous on R Solution • (a) A function f R → R is uniformly continuous if for every ϵ > 0 there exists δ > 0 such that f(x)−f(y) < ϵ for all x. 6 x y) n a Ò b * % U ¡ j ˝ b Ò U ¡ j a * % U ¡ j , b. ß @ 5 7 = 7 à Ü Ý 4 à Ü Ý s E @ Ü ß Ý F s ;.

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ü Strongest lib eral p o stcondition Þ n a l s t a t e s s reac hable from a g iv en precondition P ü ( X ) = Ð P f s j 9 "0 " 1 "n 2 X "0 2 P ^ s = "n g W e h a v e ( û s e t o f s t a t e s , ã_ p o in t w ise) h } ( û 1) ;. T E R M S O F S E RV I C E ­ M O O V T E C H N O L O G I E S I N C T h e se Te r m s o f S e r vi ce a r e e ff e ct i ve o n Ju n e 2 8 , 2 0 1 8. L L R T The final Equation (1) above shows that the orbital radius R can be calculated directly since the required parameters are known (namely g, L and w) The apex angle f is consequently directly obtained from the following Equation (2) ÷ ø ö ç è æ = Þ =L R R L sin f f sin 1 The apex angle f can be calculated from an alternative derivation using the conical pendulum orbital radius.

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