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This code can't be based on a onetoone match between nucleotides and amino acids because there are only four nucleotides and there are amino acids that must be coded If the nucleotides are grouped in threes, however, there are 64 possible triplets, or codons , which is more than enough combinations to code for the amino acids. F(t)dt This value is f(x) (b) d dx Z b a f(t)dt This value is zero (it’s the derivative of a constant) (c) Z b a d dx f(x)dx This value is f(b)−f(a) (d) Z b a f(x)dt This is a little tricky since the integral is in terms of t, but f is an expression in x, it will be constant with respect to t The answer f(x)(b−a) 3 Evaluate, where. If the functions were polynomials, is $(fg)(t)= f(t)g(t)$ possible?.

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